(2x^3-7x^2+5)/(x+3)

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Solution for (2x^3-7x^2+5)/(x+3) equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(2*x^3-(7*x^2)+5)/(x+3) = 0

(2*x^3-7*x^2+5)/(x+3) = 0

2*x^3-7*x^2+5 = 0

2*x^3-7*x^2+5 = 0

{ 1, -1, 5, -5 }

1

x = 1

2*x^3-7*x^2+5 = 0

1

x-1

2*x^2-5*x-5

2*x^3-7*x^2+5

x-1

2*x^2-2*x^3

5-5*x^2

5*x^2-5*x

5-5*x

5*x-5

0

2*x^2-5*x-5 = 0

DELTA = (-5)^2-(-5*2*4)

DELTA = 65

DELTA > 0

x = (65^(1/2)+5)/(2*2) or x = (5-65^(1/2))/(2*2)

x = (65^(1/2)+5)/4 or x = (5-65^(1/2))/4

x in { (5-65^(1/2))/4, (65^(1/2)+5)/4, 1} 

(x-((5-65^(1/2))/4))*(x-((65^(1/2)+5)/4))*(x-1) = 0

((x-((5-65^(1/2))/4))*(x-((65^(1/2)+5)/4))*(x-1))/(x+3) = 0

( x-((5-65^(1/2))/4) )

x-((5-65^(1/2))/4) = 0 // + (5-65^(1/2))/4

x = (5-65^(1/2))/4

( x-((65^(1/2)+5)/4) )

x-((65^(1/2)+5)/4) = 0 // + (65^(1/2)+5)/4

x = (65^(1/2)+5)/4

( x-1 )

x-1 = 0 // + 1

x = 1

x in { (5-65^(1/2))/4, (65^(1/2)+5)/4, 1 }

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